Schwartzman’s record against his group members at the ATP Finals


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Schwartzman's record against his group members at the ATP Finals

Finally, the two groups were defined for the ATP Finals in London, the contest that will begin next Sunday and will bring together the eight best tennis players on the circuit.

The Peque will share his group with Novak Djokovic, Daniil Medvedev and Alexander Zverev. First of all, in front of the Serbian, the Argentine does not have a good record: in the duels between the two, The current world number 1 leads the head-to-head with a resounding 5-0 advantage. The first victory was in the US Open 2014 6-1, 6-2, 6-4, then in Roland Garros 2017 by 5-7, 6-3, 3-6, 6-1 and 6-1 and two years later in the Rome Masters 1000 in 2019 by 6-3, 6-7 (2) and 6-3. This year, Nole won the wins at the Australian Open by 6-3, 6-4 and 6-4 and in the final of Rome Masters 1000 by 7-5 and 6-3.

Then appears Medvedev, to whom Schwartzman also failed to win a game in his career, with a 0-4 record. The most recent antecedent occurred in the last edition of the Paris Masters 1000, in which the Peque fell to the Russian in the quarterfinals by 6-3 and 6-1. The first clash between the two was in Tokyo 2018, with victory for Daniil by 6-4 and 6-4. Then they clashed in Queen’s 2019, with a new victory for Medvedev by 6-2 and 6-2, and they also saw their faces in the ATP Cup this year in Australia, in which the Russian defeated the Argentine 6-4, 4-6 and 6-3.

Finally share a group with Zverev, with whom he has a more equal record: two wins for each. The Peque stayed with the victories in Kitzhubel in 2014 by 6-1 and 6-0 and in the 16th final of the US Open 2019 by 3-6, 6-2, 6-4 and 6-3. For his part, the German celebrated against the Argentine at the Paris Masters 1000 in 2018 by 6-4 and 6-2, and in the last edition of Cologne 2, by consecrating themselves in the grand final 6-2 and 6-1.


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